So long as the <br/> elements are children of the <p> element (not
descendants), you can use
<xsl:for-each-group group-starting-with="br">
This will include the br element as a member of the group, but you can
easily lose it using
current-group()[not(self::br)]
(You can use group-ending-with="br" as well, but if you drop the br elements
the effect is identical).
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Georges Schmitz [mailto:georges(_dot_)schmitz(_at_)heitec(_dot_)de]
Sent: 07 November 2006 13:47
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] "Line"-Tokenizing at <br/> in xhtml
Tokenizing a string at LFs and putting <br/> in place of
them is well known to me (in XSLT2.0), but for the moment I'm
stuck with the other way round.
I have something like this (xhtml):
<p>blabla blabla <br/>
blabla blabla blabla <br/>
blabla <b>blabla</b> blabla <br/>
blabla blabla blabla</p>
I need to have access to every single "line" (terminated by
<br/>), preserving the mixed content of the lines.
1. The tokenize() function as well as the analyze-string
method only
operate on strings, not on mixed content.
2. <for-each select=".//text()"> (just posted some days
ago) doesn't
work because of line 3, and
3. <xsl:for-each select="br">
<xsl:value-of select="preceding-sibling::text()[1]"/>
</xsl:for-each>
a) doesn't work because of line 3
b) I would have to fetch the last line separately
Thanks for any advise,
Georges Schmitz
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