Please try the technique illustrated in the following stylesheet:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="text" />
<xsl:template match="/test">
<xsl:value-of select="count(B[generate-id() =
generate-id(following-sibling::C[1]/preceding-sibling::B[1])])" />
</xsl:template>
</xsl:stylesheet>
The above stylesheet prints 2, when applied to the given XML.
On 12/6/06, Ken Tam <kentam(_at_)proteustech(_dot_)com> wrote:
Hi all,
I would like to count the number of occurence from B -> C but not the
overlaps. For example,
<test>
<A></A>
<B></B>
<F></F>
<C></C>
<D></D>
<B></B>
<C></C>
<E></E>
<C></C>
<C></C>
</test>
Only,
B->F->C
B->C
should be counted. I tried /test/B/following-sibling::*[contains(name(),
'C')] but this doesn't work as the other "C" siblings are counted as well.
This is the expected behavior of following-sibling. How can I filter out the
unwanted siblings?
Thanks,
kkt
--
Regards,
Mukul Gandhi
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