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RE: [xsl] Special character as element name

2007-01-25 01:46:53
XSLT transforms XML to XML. <#x> is not well-formed XML, so you can't
produce it using XSLT.

Michael Kay
http://www.saxonica.com/

 

-----Original Message-----
From: San [mailto:san_sar(_at_)yahoo(_dot_)com] 
Sent: 25 January 2007 08:20
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Special character as element name

Dear all,

Many thanks for answering my questions the other day.
Now I encounter some problem, I search for the answer but 
haven't got the right one.(using version 1.0 and
xalan)

Also This is my xml input file

<Query ID="2" >
  <QueryHead URI="#x">
  </QueryHead>
</Query>
                      
I would like to have the output (getting the attributes 
value) as the element name

<Body ID="2" >
  <#x/>
</Body>

I am trying using this xslt file (below), which ok if the 
attributes value not special character (X without #)but not #x

<Body>
  <xsl:element name="{//Query/@URI}"/>        
</Body>

I tried several possibility, first I used the unicode for 
replacing this # with hexadecimal. stil not work, then I 
change the encoding type in the xslt file

<?xml version="1.0" encoding="iso-8859-1"?> 

<xsl:output method="xml" indent="yes"  
encoding="ISO-8859-1"/> 

Stil doesn't give me result. 
I really stuck with this :(

thanks a lot for your help
san



 
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