Michael Kay wrote:
Not sure why you are using index-of (or some, for that matter). It looks to
me like
$fib[1] = 0 and $fib[2] = 1 and
every $i in 2 to count($fib) satisfies
$fib[$i] = $fib[$i - 1] + $fib[$i - 2]
Aha! (erlebnis)
Thanks, Michael. It was one of those problems I can look at forever
without 'seeing' the inverse-logic algorithm you present me here.
Instead of going through the objects and 'satisfying' from each object
(hence trying index-of to find near-by objects), I should've used a
simple range operator and indices instead.
This definitely clears up my mind for several lock-up problems (and I
shouldn't stay up too late ;)
(or some, for that matter)
That was a typo, the example problem only works, of course, with
'every', I have some other cases where 'some' is required.
Cheers!
-- Abel
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