Abel Braaksma wrote:
Hi
Abel Braaksma wrote:
Michael Kay wrote:
$fib[1] = 0 and $fib[2] = 1 and
every $i in 2 to count($fib) satisfies
$fib[$i] = $fib[$i - 1] + $fib[$i - 2]
Here's another version, which eases the expression a bit
by removing the special cases:
every $i in 1 to count($fib) satisfies
$fib[$i] = (0, $fib)[$i] + (0, 1, $fib)[$i]
Personally, I like the first version. The second one is
shorter, but the first one as is almost a literal
translation from the mathematical definition. But it is a
matter of taste, I guess.
Regards,
--drkm
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