Define the elements as members of a substitution-group S in the schema, then
you can do
select="/objects/object/schema-element(S)"
Or do
select="/objects/object//(list|box|group)"
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: tom tom [mailto:tomxsllist(_at_)hotmail(_dot_)com]
Sent: 21 February 2007 12:29
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Selecting a group of elements with different names
Hi all,
i need to select a group of elements whose name belongs to a
defined list - something along the lines of:
<xsl:for-each-group
select="/objects/object//*[name() ='list' or name()='box' or
name()='group']" group-by="concat(name(), @type)">
Using XSLT 2 Can you suggest a more elegant way to list the
element names
than:
name() ='list' or name()='box' or name()='group'
?
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