Thanks David for your help.
I am working on XSLT 1.0.
not sure what you mean by top element. If you mean ancestor then in 2
that's
key('ParentKey',@id) intersect ancestor::category
By saying top element, I mean all ancestors of the current element.
Could you please tell me what the above syntax would be in XSLT 1.0.
- R
----- Original Message ----
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Sent: Wednesday, March 7, 2007 12:40:19 PM
Subject: Re: [xsl] Key to select all same nodes(same @id) except current node
best to say of you want xslt1 or 2.
in 2
key('ParentKey',@id) except .
will return all category elements with the current id except the current
node.
in 1 you'd write it as
key('ParentKey',@id)[not(generate-id()=generate-id(current()))]
Also I want to check whether any <category> elements
with same @id, exists in all top elements of current
<category> element.
not sure what you mean by top element. If you mean ancestor then in 2
that's
key('ParentKey',@id) intersect ancestor::category
David
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