Thanks Michael. :)
<xsl:for-each
select="key('ParentKey',@id)[not(generate-id()=generate-id(current()))]">
<xsl:variable name="parentvar" select="."> <!-- it selects
current node, Needs to check whether its grand parent is 'category or not' -->
</xsl:variable>
<xsl:if test="name(ancestor::$parentvar[2]) = 'category'">
<samenode>
<xsl:value-of
select="ancestor::$parentvar[2]/@id"></xsl:value-of>
</samenode>
</xsl:if>
</xsl:for-each>
Could you please tell me what is wrong in xpath "ancestor::$parentvar[2]" . It
gives error saying it is not a valid xpath.
- R
----- Original Message ----
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Sent: Wednesday, March 7, 2007 1:52:51 PM
Subject: RE: [xsl] Key to select all same nodes(same @id) except current node
I need a clarification on child::category. Does it returns
all child category elements of current element?
Yes.
If my structure is
<category>
<list>
<category>
</category>
</list
</category>
so will it return inner category element?
Yes, if the current element is "list".
Michael Kay
http://www.saxonica.com/
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