You can do all of this with template rules, you don't need xsl:choose at
all. Write rules like
<xsl:template match="table[(_at_)style='simple']">
<xsl:template match="table[(_at_)style='simple']/tr">
<xsl:template match="table[(_at_)style='simple']/tr/td">
to process the different kinds of element in your input.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Thomas Zastrow [mailto:listen(_at_)thomas-zastrow(_dot_)de]
Sent: 22 March 2007 18:19
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Templates for different kinds of tags?
Hi there,
I'm not so familiar with XSL, please be patient ;-)
I have a XML-document (not HTML) with tables like this:
<table>
<tr>
<td></td><td></td>
</tr>
</table>
So, I have three templates for them:
<xsl:template match="table">
<xsl:template match="tr">
<xsl:template match="td">
Now, I want to use different kinds of tables in my XML-doc like
<table style="simple">
<table style="xyz">
Depending on the style-attribut, I can change the
template-code for <table> with xsl:choose. But, the <tr>-
and <td>-tags are still the same code, so, they will always
use the same templates. But I also want to change the code
for tr and td, depending on the style of the complete table.
Is this possible or have I to write the xsl:choose -
statement again in the tr- and in the td-templates?
Thank you!
Best,
Tom
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