It's not possible with pure XSLT to generate XML that isn't
namespace-well-formed (for example, XML that uses a namespace prefix that
isn't declared). Does JSP/JSTL really require that?
Your best bet for achieving this output is to do some non-XSLT
post-processing of the XSLT result tree, for example generate the element
names as c_choose and then post-process to convert that to c:choose. You
could do that easily enough by sending the transformation output to a
SAXResult.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Kai Weber [mailto:weber(_at_)mediaworx(_dot_)com]
Sent: 24 April 2007 18:03
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Generating JSP/JSTL
Hello,
In the archives I found one with a similar problem:
http://www.biglist.com/lists/xsl-list/archives/200102/msg01662.html
Just to recap and to bring my problem to some attention: I
want to create a JSP with some JSTL for later processing on a
application server.
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:c="http://java.sun.com/jsp/jstl/core";
exclude-result-prefixes="c"
version="2.0">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:template match="/"> <ul>
<c:choose>
foo
</c:choose>
</ul>
</xsl:template>
The target document should look like
<ul>
<c:choose>
foo
</c:choose>
</ul>
But this it what it looks:
<ul>
<c:choose xmlns:c="http://java.sun.com/jsp/jstl/core";>
foo
</c:choose>
</ul>
Is it possible to achieve the wanted result and omit the
xmlns declaration in each element?
Grüße,
Kai Weber
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