<xsl:for-each select="file">
that iterates over all the file elements
<xsl:variable name="filename" select="file"/>
that selects the file element child of the current node (which is the
file element) in your example this is empty in all cases.
you want
<xsl:variable name="filename" select="."/>
<xsl:sort order="descending" select="document($filename)/date">
xsl:sort has to be the first child of xsl:for-each
you could you want
<xsl:for-each select="document(file)">
<xsl:sort select="date"/>
<xsl:value-of select="date"/>
</xsl:for-each>
but that just gives the date (this assumes based on your example xpath
<xsl:value-of select="document($filename)/date">
that file1.xml _only_ has a single date element
in xslt2 if you also weant the filename you could change that to
<xsl:for-each select="document(file)">
<xsl:sort select="date"/>
<xsl:value-of select="base-uri(),date"/>
</xsl:for-each>
But in xslt1 if you want the names you need to save them before you move
into the file:
<xsl:for-each select="file">
<xsl:sort select="document(file)/date"/>
<xsl:value-of select="."/>
<xsl:text> </xsl:text>
<xsl:value-of select="document(file)/date"/>
</xsl:for-each>
David
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