On 5/15/07, Vaduvoiu Tiberiu <vaduvoiutibi(_at_)yahoo(_dot_)com> wrote:
I want to sort an xml document by data from an external document. Let me see if
I can explain this: I have list.xml:
<list>
<file>file1.xml</file>
<file>file2.xml</file>
...
<file>file100.xml</file>
<list>
each of the fileX.xml have inside a date tag:
<date>20071015102000</date>(yyyymmddhhmmss). I want to sort the list.xml by the
date in each file. The way I did it:
<xsl:for-each select="file">
<xsl:variable name="filename" select="file"/>
<xsl:sort order="descending" select="document($filename)/date">
File: <xsl:value-of select="."> Date: <xsl:value-of
select="document($filename)/date">
</xsl:for-each>
The variable $filename is selecting the child <file> of the <file>
element selected by the for-each, which doesn't exist so the sort
value is empty each time. So change
<xsl:variable name="filename" select="file"/>
to:
<xsl:variable name="filename" select="."/>
...although you probably want:
<xsl:for-each select="document(file)">
<xsl:sort select="/path/to/date"/>
....
as then the context node is the root of the document referenced by
document() and not the <file> element in the list.
cheers
andrew
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--