[xsl] Extract input filename

Dear Friends-
I have no idea about to extract input filename by passing argument in 
command line. In the below examples, I don't want to hardcode "input_meta.xml".
Input files
1. input.xml
2. input_meta.xml

command line
java -jar saxon8.jar input.xml x.xsl >c.xml

Stylesheet
<xsl:variable name="filename" select="document('input_meta.xml')" />
<xsl:template match="/">
        <doi>
      <xsl:copy-of select="$filename/doi/text()" />
        </doi>
</xsl:template>

Thanks in advance.
JSR


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