1. Change this:
<xsl:variable name="filename" select="document('input_meta.xml')" />
to this:
<xsl:param name="meta" as="xs:string" required="yes"/>
<xsl:variable name="filename" select="document($meta)" />
(you might also like to change the name of the variable filename, as it's a
misleading name)
2. Change your command line to
java -jar saxon8.jar input.xml x.xsl meta=input_meta.xml >c.xml
Michael Kay
http://www.saxonica.com/
I have no idea about to extract input filename by passing
argument in command line. In the below examples, I don't want
to hardcode "input_meta.xml".
Input files
1. input.xml
2. input_meta.xml
command line
java -jar saxon8.jar input.xml x.xsl >c.xml
Stylesheet
<xsl:variable name="filename" select="document('input_meta.xml')" />
<xsl:template match="/">
<doi>
<xsl:copy-of select="$filename/doi/text()" />
</doi>
</xsl:template>
Thanks in advance.
JSR
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