-----Original Message-----
From: Charles Ohana [mailto:charles(_dot_)ohana(_at_)buongiorno(_dot_)com]
Sent: 12 June 2007 15:11
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] replace
Thank you. but ... I still have issues. The following code
returns the eror below. I must be missing something.
Error in expression replace(@name, 'Chuck', 'Charles'): Unknown system
function: replace
Transformation failed: Run-time errors were reported
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/cnt">
<xsl:value-of select="replace(@name, 'Chuck', 'Charles')" />
</xsl:template>
</xsl:stylesheet>
----- Original Message -----
From: "David Carlisle" <davidc(_at_)nag(_dot_)co(_dot_)uk>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Tuesday, June 12, 2007 9:05 AM
Subject: Re: [xsl] replace
I want to replace "a" by "b"
the code you posted, with Michael's change, would do that
assuming teh
EXSLT template is at the location implied by you rxsl:import.
inside "/root/@description" .
I suspect that you mean that you want to output the rest of
the document
unchanged, except for this change. XSLT will not do that
automatically
you neeed to add an "identity template" that copies each
node from the
input to the output. (google for modified identity
tramsformation, or
see examples in the faq or Jeni's site) the code you posted
would just
output the string value of the @description output, with
the replacement
made.
In XSLT2 you don't need any replace templates, just
select="replace(@description,'a','b')
will do the job.
Actually if you real example is a single letter you don't
need anything
other than
select="translate(@description,'a','b')
which would also work in xslt 1
David
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