The simplest change to your code is to add an xsl:sort to your for-each that
sorts the matching nodes by descending depth. That's <xsl:sort
select="count(ancestor::node)" order="descending"/>. Then you can return a
value only when position()=1.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: J. Zhang [mailto:j(_dot_)zhang(_at_)uva(_dot_)nl]
Sent: 12 July 2007 15:47
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Select Deepest Node only in Iteration
I have already checked the XSL FAQ at
http://www.dpawson.co.uk/ and explored the history of this
mailinglist. I could not find the answer, that is why I am
posting here.
I am matching the content of XML elements this way in a
for-each iteration:
xsl:if test="matches(string(self::node()), concat('\W',
$term, '\W'), 'im')">
I return the absolute path where $term occurs in the
transformation. The result after the transformation is for
example this for Word 1:
//article
//article/body[1]
//article/body[1]/section[6]
//article/body[1]/section[6]/normallist[6]
//article/body[1]/section[6]/normallist[6]/item[1]
The problem is that I only want the longest path, e.g. the
deepest node of this leave. I need to set a condition that
only returns something when the for-each iteration has come
to the longest path of this leave, but I could not find a way
to do this.
Any help would be greatly appreciated! Thanks!
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