A problem, reversing (descending) works, but selecting the top of the
list does not work. I have been testing by outputting some numbers from
the following 2 functions.
<a><xsl:value-of select="count(ancestor::node())"/></a>
<b><xsl:value-of select="position()"/></b>
This the output I am getting for the first item in the list:
<a>5</a>
<b>74</b>
So the position() function does not work in my case. That is why I think
I need to match in an if statement with count(ancestor::node()), e.g.
<xsl:if test="count(ancestor::node())=5">
Then I am getting the top of the list, a problem is however that I am
reading multiple documents and match with multiple keywords. So I cannot
set it adhoc this way. What I did find out is that the first item in the
reversed list is the highest number for each leaf.
The only question is: is there a function to replace the "5" in the if test?
I hope you understand my problem. Thanks!
David Carlisle wrote:
xsl:sort has to be the first child of the xsl:for-each, so move it up a
couple of lines.
David
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