mike(_at_)saxonica(_dot_)com schrieb am 24.07.2007 12:29:21:
In trying to reverse-engineer your code, it looks to me as if you are
doing
a classic "group-adjacent" problem, where a group of adjacent row
elements
are wrapped in a table element.
thats it!
The key point I think is that it's usually not necessary. In the vast
majority of cases there is a way of solving the performance problems
that
doesn't require you to write bad code.
I think I found one way with your help/hint of recursive templates.
The code:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:apply-templates select="*" />
</xsl:copy>
</xsl:template>
<xsl:template match="row[position() = 1 or
preceding-sibling::*[name() != 'row' and position() = 1]]" >
<table>
<xsl:apply-templates select="." mode="more2come"/>
</table>
</xsl:template>
<xsl:template match="row" mode="more2come">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:apply-templates select="*" />
</xsl:copy>
<xsl:if test="following-sibling::*[name() = 'row' and
position() = 1]">
<xsl:apply-templates
select="following-sibling::row[position() = 1]" mode="more2come" />
</xsl:if>
</xsl:template>
<xsl:template match="row" >
</xsl:template>
</xsl:stylesheet>
It was much easier than the solution with <xsl:key>. But I learned much
about XPath.
Thank you for helping me to find a way..
Christoph Naber
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