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[xsl] RE: bad programming for speedup?

2007-07-24 07:43:49
Hello,

I'm sorry that my imprecise description of the problem caused some 
confusion.

I'm using XSLTPROC for transformation, which AFAIK only supports XSLT 1.0. 
I had written a mail with input/output examples but I did not send it when 
I received the recursion-hint from Michael, sorry for that.

Have you tried the other suggestions? Mainly Andrew's method (or mine 
even, if the below does what I think it does).

I just edited the stylesheet according to Justins suggestions. And I read 
through Andrew's method. This way to code XSLT is very new for me. I 
learned XSLT at the university, but as you (and me too) may have already 
noticed, the professor only taught us the very basics.

Please allow me to make some suggestions on your code below:

The more, the better.

I tried to rewrite the stylesheet. I think its better not to post my 
version with the key here to avoid more "eyes that hurt" :)

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
        <xsl:output method="xml" indent="yes"/>
 
        <xsl:template match="node() | @*">
                <xsl:copy>
                        <xsl:apply-templates select="@* | node()[1]" />
                </xsl:copy>
                <xsl:apply-templates select="following-sibling::*[1]" />
        </xsl:template>
 
        <xsl:template match="row" >
                <table>
                        <xsl:apply-templates select="." mode="more2come"/>
                </table>
                <xsl:apply-templates select="following-sibling::*[ 
not(self::row)][1]" />
        </xsl:template>

        <xsl:template match="row" mode="more2come">
                <xsl:copy>
                        <xsl:apply-templates select="@* | node()[1]" /> 
                </xsl:copy>
                <xsl:apply-templates 
select="following-sibling::*[1][self::row]" mode="more2come" />
        </xsl:template>
 
</xsl:stylesheet>


Thank you all for your answers, I'm very astonished about so much response 
to a dumb question.

Greets
Christoph Naber


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