this helps me too - excellent
--- Wasiq Shaikh <wasiq911(_at_)hotmail(_dot_)com> wrote:
Ah, I see! When I printed the variable it "looked"
like a nodeset, so I
assumed I could access the elements and attributes
within.
This is my working solution after applying Mukul's
suggestion. Thanks Mukul!
<xsl:variable name="validAttributeType">
<xsl:if test="key('allTypes', @type)">
<xsl:copy-of select="key('allTypes',
@type)/xsd:restriction"/>
</xsl:if>
<xsl:if test="xsd:simpleType">
<xsl:copy-of
select="xsd:simpleType/xsd:restriction"/>
</xsl:if>
</xsl:variable>
<xsl:if test="$validAttributeType!=''">
<xsl:element name="validValues">
<xsl:call-template name="trimAttribute">
<xsl:with-param name="attributeName"
select="'base'"/>
<xsl:with-param name="attribute"
select="xalan:nodeset($validAttributeType)/*/@base"/>
</xsl:call-template>
<xsl:for-each
select="xalan:nodeset($validAttributeType)/*/*">
<xsl:element name="value">
<xsl:attribute name="type">
<xsl:value-of
select="substring-after(name(),
'xsd:')"/>
</xsl:attribute>
<xsl:value-of select="@value"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:if>
(using XalanJ 2.7/XPath 1.0)
----Original Message Follows----
The error you are getting at this line,
<xsl:with-param
name="attribute"
select="$validAttributeType/@base"/>
is because the variable "validAttributeType" is a
result tree fragment
(it's a special data type defined in XSLT 1.0), and
you are trying to
apply an XPath operation to it; which is not
correct.
To my opinion, you need to use an extension function
node-set for this
(if you are restricted to XSLT 1.0).
So for example, something like following will work:
<xsl:with-param name="attribute"
select="xx:node-set($validAttributeType)/xsd:restriction/@base"/>
(please bind the prefix xx to the required namespace
- please see the
product documentation for this)
With XSLT 2.0, you will not get the error at all,
for the operation
you are trying to do (because XSLT 2.0 implicitly
treats the contents
of xsl:variable in this case as a node-set).
On 8/1/07, Wasiq Shaikh <wasiq911(_at_)hotmail(_dot_)com>
wrote:
> Hi,
>
> I'm setting a value on a variable using
conditions. The variable must be
a
> node-set so that I can do some processing with
it.
>
> <xsl:variable name="validAttributeType">
> <xsl:if test="key('allTypes', @type)">
> <xsl:copy-of select="key('allTypes',
@type)/xsd:restriction"/>
> </xsl:if>
> <xsl:if test="xsd:simpleType"
> <xsl:copy-of
select="xsd:simpleType/xsd:restriction"/>
> </xsl:if>
> </xsl:variable>
>
> The "xsd:restriction" tag has a "base" attribute
that I need to access
and
> send to a template as a parameter.
>
> <xsl:call-template
name="trimAttribute">
> <xsl:with-param
name="attributeName" select="'base'"/>
> <xsl:with-param name="attribute"
> select="$validAttributeType/@base"/>
> </xsl:call-template>
>
> But it gives me a "XSLT Error
(javax.xml.transform.TransformerException):
> org.apache.xpath.objects.XRTreeFrag" when I try
to do
>
> <xsl:with-param name="attribute"
select="$validAttributeType/@base"/>
> OR
> <xsl:with-param name="attribute"><xsl:copy-of
>
select="$validAttributeType/@base"/></xsl:with-param>
>
> I can print out the variable's contents, which is
correct, but I can't
seem
> to access the attribute. By the way, previously I
had this
>
> <xsl:variable name="validAttributeType"
select="key('allTypes',
> @type)/xsd:restriction"/>
>
> which works! But adding the conditional messed it
up. How can I get the
same
> behaviour as the above line in a conditional
variable?
>
> I appreciate any help. Thank you!
--
Regards,
Mukul Gandhi
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