OK, thanks, I think it might. I'll mull it over.
following has context node a for position(), but beware, it is in the
third predicate, so it counts only the subset selected by the earlier
predicates.
a[count(b/c/*) = '12'][b[(_at_)x = 'rr']][position() = 2]
HTH,
-- Abel Braaksma
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