Riku
Probably your variable is out of scope. Was it decalred in a different
template?
Joe
http://joe.fawcett.name
From: Riku Riikonen <riku(_dot_)riikonen(_at_)uta(_dot_)fi>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XSL generating PHP/MySQL
Date: Thu, 27 Sep 2007 22:28:07 +0300
Hello
I'm pushing xml through xsl and trying to have php code.
Can anyone help and tell me what i'm doing wrong in my xsl? (here comes
just the problematic part)
<xsl:choose>
<xsl:when test="CASE1">
<xsl:text>
mysql_query("</xsl:text><xsl:value-of select='concat("SET
","@","index=LAST_INSERT_ID()")' /><xsl:text>");
$index="@index";</xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:choose>
<xsl:when test="CASE2">
<xsl:text>$index='20'</xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:text>$index='0';</xsl:text>
</xsl:otherwise>
</xsl:choose>
</xsl:otherwise>
</xsl:choose>
<xsl:text>
</xsl:text>
<xsl:text>mysql_query("</xsl:text><xsl:value-of select='concat("replace
into table (index,variable) values
('",$index,"','",$variable,"')")'
/><xsl:text>");</xsl:text>
After XSLT process i is said that variable index has not been declared.
Variable called variable has been declared elsewhere.
I tried to use following
<xsl:variable name="index">$index</xsl:variable>
, but it didn't work.
Can anyone help me out?
BR
Riku
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