Ignoring namespaces, it's:
<xsl:copy-of select="/AllUnitInfos/UnitInfos/UnitInfo[Type =
document('selection.xml')/UnitInfos/Type"/>
In 2.0, specify xpath-default-namespace="Animals".
In 1.0, prefix each name in the expression above with "a:" and bind
xmlns:a="Animals" in the stylesheet.
Michael Kay
http://www.saxonica.com/
Input file:
<AllUnitInfos xmlns="Animals">
<UnitInfos>
<UnitInfo>
<Class>UNITCLASS_LION</Class>
<Type>UNIT_LION</Type>
<bla/>
</UnitInfo>
<UnitInfo>
<Class>UNITCLASS_CAT</Class>
<Type>UNIT_CAT</Type>
<bla/>
</UnitInfo>
<UnitInfo>
<Class>UNITCLASS_WOLF</Class>
<Type>UNIT_WOLF</Type>
<bla/>
</UnitInfo>
<UnitInfo>
<Class>UNITCLASS_DOG</Class>
<Type>UNIT_DOG</Type>
<bla/>
</UnitInfo>
<UnitInfos>
</AllUnitInfos>
My Selection list:
<UnitInfos xmlns="Animals">
<Type>UNIT_LION</Type>
<Type>UNIT_DOG</Type>
</UnitInfos>
According to my selection List, I would like to copy all
UnitInfo elements with their children that have a type
element which is listed in
the small list above.
Output should be this:
<AllUnitInfos xmlns="Animals">
<UnitInfos>
<UnitInfo>
<Class>UNITCLASS_LION</Class>
<Type>UNIT_LION</Type>
<bla/>
</UnitInfo>
<UnitInfo>
<Class>UNITCLASS_DOG</Class>
<Type>UNIT_DOG</Type>
<bla/>
</UnitInfo>
<UnitInfos>
</AllUnitInfos>
The list above could be placed in a file or anywhere that
would make it possible/easier.
Many thanks for any idea,
Houman
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