<xsl:copy>.....</xsl:copy>
does a shallow copy of the current node. Think of it as copying the element
tags, and then invoking the nested instructions to create the element
content (that's not really what happens, there aren't any tags in the tree,
but it's a first-order approximation).
<xsl:copy-of select="@*"/>
says copy the attributes of the current element unchanged
<xsl:apply-templates/>
says process each child of the current element using its appropriate
template rule. That's either the generic identity template (invoked
recursively), or the special template for the one element you want to
change.
Michael Kay
http://www.saxonica.com/
does xsl:copy copy all the descendants of the current node?
If yes, then it will copy the node which was intended to
change through some template, right?
If no, then how do the descendants of the current node get copied?
Thanks,
J
On 10/2/07, Martin Honnen <Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
John Smith wrote:
That works perfectly, thanks. But what actually happens here:
<xsl:copy><xsl:copy-of
select="@*"/><xsl:apply-templates/></xsl:copy>
xsl:copy copies the current node. xsl:copy-of select="@*"
copies any
attribute nodes. xsl:apply-templates processes all child nodes.
--
Martin Honnen
http://JavaScript.FAQTs.com/
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