xsl-list
[Top] [All Lists]

[xsl] Passing a list of arguments

2007-11-09 04:20:26
Hello,

  I have a list of arguments to pass to my XSLT. I thought that I
could simply construct a small XML tree to do that. I do not
understand why the list argument tree is being expanded. How was I
supposed to do that ?

Thanks
-Mathieu

test.xml:
<?xml version="1.0" encoding="UTF-8"?>
<article>
</article>

test.xsl:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>
  <xsl:variable name="sections-list">
    <section>
      <section>C.8.7.1.1.2</section>
      <section>C.8.14.1.1</section>
      <!-- ... -->
    </section>
  </xsl:variable>
  <xsl:template match="article">
    <xsl:param name="extract-section"/>
    <xsl:message>
      <xsl:value-of select="$extract-section"/>
    </xsl:message>
  </xsl:template>
  <xsl:template match="/">
    <xsl:for-each select="$sections-list">
      <xsl:apply-templates select="article">
        <xsl:with-param name="extract-section" select="$section"/>
      </xsl:apply-templates>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>


-- 
Mathieu

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>