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Re: [xsl] Passing a list of arguments

2007-11-09 06:38:56
Hi Mukul,

On Nov 9, 2007 2:16 PM, Mukul Gandhi <gandhi(_dot_)mukul(_at_)gmail(_dot_)com> 
wrote:
You seem to be missing something.

I think, the root template should be:

 <xsl:template match="/">
   <xsl:for-each select="$sections-list/section/section">
     <xsl:apply-templates select="article">
       <xsl:with-param name="extract-section" select="."/>
     </xsl:apply-templates>
   </xsl:for-each>
 </xsl:template>


This is better. In this case for-each is operating on each element of
sections/section

It's not clear to me what exactly is your requirement. But you seem to
be writing a wrong XPath expression.

But for some reason applying the template does not work, the value
from sections/section is not passed... Using a call-template works but
this is not what I would like.

Thanks,
-- 
Mathieu

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