At 2007-11-28 10:46 -0500, Terry Ofner wrote:
I do have a more general question/clarification that perhaps someone
can address.
Say I want to replace an element and its attributes with a new
element name and attribute(s). Say I also want to keep the mark-up of
the content. I have noticed that if I use <xsl:value-of select "."/>
the content mark-up is stripped out. So with this content:
<test>
<selection name="u1pt01">
<para> text, more text, <i>italic text.</i> </para>
</selection>
</test>
The following template would strip out the <i> tags,
<xsl:template match="selection">
<para aim:pstyle='bodytext'><xsl:value-of select "para"/><para>
</xsl:template>
producing
<test>
<selection name="u1pt01">
<para aim:pstyle='bodytext'> text, more text, italic text. </para>
</selection>
</test>
Am I correct?
Yes. The value of an element node is the concatenation in document
order of all descendent text nodes.
To avoid stripping content mark-up, I need to use <xsl:copy-of select
"para"/>. When I do that, however, I get two <para> tags.
You could use <xsl:copy-of select="para/node()"/> if you don't need
to intervene on the descendent nodes, but perhaps using
apply-templates and the identity template you would have a more
general solution.
With copy-of, is it still possible to replace elements and
attributes?
No.
I suspect that I am missing something very basic. Some
clarification would be great.
copy-of copies the nodes without an opportunity for intervention ...
for intervention, use apply-templates.
I hope this helps.
. . . . . . . . . . . . Ken
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