Hello all,
In XSLT 2.0, is it possible to define the output document type by
stylesheet parameters? I've tried this without success by the following
method:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="doctype.system" select="string('commbook.dtd')"/>
<xsl:param name="doctype.public"
select="string('-//JMP//DTD DocBook V4.4-Based Subset
V0.1//EN')"/>
<xsl:output method="xml" version="1.0" encoding="utf-8"
doctype-system="{$doctype.system}"
doctype-public="{$doctype.public}" />
I expect to get this output:
<!DOCTYPE chapter PUBLIC "-//JMP//DTD DocBook V4.4-Based Subset
V0.1//EN" "commbook.dtd">
But instead receive this output:
<!DOCTYPE chapter PUBLIC "{$doctype.public}"
"{$doctype.system}">
I know this type of thing wasn't possible in 1.0, but it seems like it
might be in 2.0. Is there another approach I should be using, or am I
out of luck? I'm using Saxon 9B.
Thanks,
-James
-----
James Sulak
Electronic Publishing Developer
Jones McClure Publishing
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