Oh, sorry. Read too fast.
Dmitry probably has this handled in FXSL (or will :) )
best,
-Rob
On Fri, 2008-02-22 at 14:08 +0000, Andrew Welch wrote:
The goal is to give you all possible words that can be made out of a given
word.
So for "farmer" you get:
framer
armer
farer
frame
rearm
fame
fare
...
So I'm looking for a comparison that checks if a word can be made out
of the letters of another word.
The recursive function that I wrote 10 mins ago looks like this, where
$searchWord would be the codepoints for "farmer", and $wordListWord
would be any word from my list of words:
<xsl:function name="f:checkWord" as="xs:boolean">
<xsl:param name="searchWord" as="xs:integer*"/>
<xsl:param name="wordListWord" as="xs:integer*"/>
<xsl:variable name="firstChar" select="$wordListWord[1]"
as="xs:integer?"/>
<xsl:choose>
<xsl:when test="empty($wordListWord)">
<xsl:sequence select="true()"/>
</xsl:when>
<xsl:when test="empty($searchWord)">
<xsl:sequence select="false()"/>
</xsl:when>
<xsl:when test="$firstChar = $searchWord">
<xsl:sequence select="f:checkWord(remove($searchWord,
index-of($searchWord, $firstChar)[1]), remove($wordListWord, 1))"/>
</xsl:when>
<xsl:otherwise>
<xsl:sequence select="false()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:function>
On 22/02/2008, Robert Koberg <rob(_at_)koberg(_dot_)com> wrote:
contains(str1, str2)
?
On Fri, 2008-02-22 at 13:57 +0000, Andrew Welch wrote:
> A bit of a Friday challenge...
>
> Is it possible to compare to sequences such that items in the sequence
> are consumed after the comparison?
>
> For example, I want to compare two words to see if one is a subset of
the other.
>
> "farmer" and "frame"
>
> If you do:
>
> string-to-codepoints('farmer')[not(. = string-to-codepoints('frame'))]
>
> the result is empty because the two r's in farmer are both being
> compared to the single r in frame.
>
> Currently I've a got a recursive function that removes each letter
> after a match, but I'm wondering if there's a one-liner or some other
> set based approach?
>
>
> thanks
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