Thank you very much. It works perfectly.
Raymond
-----Original Message-----
From: Florent Georges [mailto:lists(_at_)fgeorges(_dot_)org]
Sent: Sunday, March 02, 2008 6:36 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Help with XPath statement
Raymond Bissonnette wrote:
I'm stuck with XSLT 1.0 (ASP.NET) and worse, what I'm after is
to get a list of <set ... > nodes with the SelectNodes method
of an XmlDocument.
I don't know XmlDocument. If you want XSLT, change <xsl:value-of
select="."/> by <xsl:copy-of select=".."/> in the solution Ken proposed
to you. If you want an XPath:
section[(_at_)id = '0802']/set[
not(@key = ../following-sibling::section/set/@key) ]
| section[(_at_)id = '0803']/set
or:
section[(_at_)id = '0802']/set[
not(@key = ../../section[(_at_)id = '0803']/set/@key) ]
| section[(_at_)id = '0803']/set
should be what you are after. Not tested!
Regards,
--drkm
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