Hi Brad,
You can put your namespace declaration for 'hdlg' on the stylesheet element
only.
I still think you should generalize your template to handle any number of
levels of directories (using recursion).
I appreciate the tips. I'll adapt them.
Thanks,
Mark
On Wed, Mar 12, 2008 at 8:53 AM, Bjorndahl, Brad
<brad(_dot_)bjorndahl(_at_)thermofisher(_dot_)com> wrote:
Mark,
I'm glad this works for you. I have a few comments if you don't mind.
I used the term 'regression' incorrectly in my previous replies. I should
have used 'recursion'.
You can put your namespace declaration for 'hdlg' on the stylesheet element
only.
I still think you should generalize your template to handle any number of
levels of directories (using recursion).
Brad
-----Original Message-----
From: Mark Peters [mailto:flickrmeister(_at_)gmail(_dot_)com]
Sent: March 12, 2008 8:04 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Processing on both a document list and referenced
documents
Hi Brad, everyone.
Here's what worked for me:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html" indent="yes"/>
<xsl:template match="hdlg:filesystem"
xmlns:hdlg="http://www.hdlg.info/XML/filesystem">
<html>
<body>
<ul>
<xsl:for-each select="hdlg:folder"
xmlns:hdlg="http://www.hdlg.info/XML/filesystem">
<li>
<xsl:value-of
select="@url"/>
<ul>
<xsl:for-each
select="document(hdlg:file/@url)"
xmlns:hdlg="http://www.hdlg.info/XML/filesystem">
<ul>
<xsl:for-each select="topic">
<li>
<xsl:value-of select="title"/>
<ul>
<xsl:for-each select="topic">
<li>
<xsl:value-of select="title"/>
<ul>
<xsl:for-each
select="topic">
<li>
<xsl:value-of select="title"/>
</li>
</xsl:for-each>
</ul>
</li>
</xsl:for-each>
</ul>
</li>
</xsl:for-each>
</ul>
</xsl:for-each>
</ul>
</li>
</xsl:for-each>
</ul>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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Saba Software
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