Off topic.
This list will never cease to amaze me. 3 valid answers, with
explanations, in 9 minutes. Kudos to all.
Alessandro
On Tue, Apr 1, 2008 at 11:19 AM, Florent Georges
<lists(_at_)fgeorges(_dot_)org> wrote:
Garvin Riensche wrote:
Hi
Can someone please tell me how I can give elements of a
subtree that are copied to the output with <xsl:copy-of
select="."> a new namespace?
The aim of xsl:copy-of is to, well, copy its arguments.
If I understand you right (but that's not sure), you want to
change the namespace URI part of the name of the elements to
copy. So that's not excatly a copy, but a transformation:
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*" priority="0">
<xsl:element name="new:{ local-name(.) }">
<xsl:apply-templates select="@*|node()"/>
</xsl:element>
</xsl:template>
That means: copy everything, except the element nodes, in this case
create a new element node whose the name is the same local-name but in
the new namespace.
Regards,
--drkm
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