think it should be like this you're looking for.
<xsl:template match="*">
<xsl:copy><xsl:apply-templates select="@*"/><xsl:apply-templates/></xsl:copy>
</xsl:template>
<xsl:template match="@*">
<xsl:copy/>
</xsl:template>
<xsl:template match="@attrib2">
<xsl:attribute name="@attrib2">0</xsl:attribute>
</xsl:template>
cheers,
Bryan Rasmussen
On Thu, Apr 10, 2008 at 10:40 AM, Karol Krenski
<mimooh(_at_)inf(_dot_)sgsp(_dot_)edu(_dot_)pl> wrote:
Hi list,
I am a novice to XSLT, learned mainly form online tutorials. This XSLT
thing is killing me. Can't figure out how to transform my doc.xml:
<?xml version="1.0" encoding="UTF-8"?>
<foo>
<bar>
<date attrib1='aaaaaaa' attrib2='bbbbbb'>25-02-08</date>
^
<name attrib3='null'>AAAAAAAAAAAAAAA</name>
</bar>
<bar>
<date attrib1='cccccc' attrib2='dddddd'>26-02-08</date>
^
<name attrib4='null'>BBBBBBBBBBBBBBB</name>
</bar>
</foo>
into
<?xml version="1.0" encoding="UTF-8"?>
<foo>
<bar>
<date attrib1='aaaaaaa' attrib2='0'>25-02-08</date>
^
<name attrib3='null'>AAAAAAAAAAAAAAA</name>
</bar>
<bar>
<date attrib1='cccccc' attrib2='0'>26-02-08</date>
^
<name attrib4='null'>BBBBBBBBBBBBBBB</name>
</bar>
</foo>
Can somebody please suggest the correct stylesheet?
I am blindly typing mainly 'copy' or 'copy-of' in my templates and the
output generation mechanics make little sense to me. The docs, comparing
to other programing documentation seems hard to understand. Could
somebody suggest good docs, please?
Regards,
Karol
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