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Re: [xsl] An (almost) identity stylesheet

2008-04-10 01:49:04
you just have to create a template for the @atttrib2:

<template match="@attrib2">
        <xsl:attribute name="@attrib2" select="'0'"/>
</template>

-- Jeff

On 04 10, 08, at 4:40 PM, Karol Krenski wrote:

Hi list,

I am a novice to XSLT, learned mainly form online tutorials. This XSLT
thing is killing me. Can't figure out how to transform my doc.xml:

<?xml version="1.0" encoding="UTF-8"?>
<foo>
    <bar>
        <date attrib1='aaaaaaa' attrib2='bbbbbb'>25-02-08</date>
                                         ^
        <name attrib3='null'>AAAAAAAAAAAAAAA</name>
    </bar>
    <bar>
        <date attrib1='cccccc' attrib2='dddddd'>26-02-08</date>
                                        ^
        <name attrib4='null'>BBBBBBBBBBBBBBB</name>
    </bar>
</foo>


into


<?xml version="1.0" encoding="UTF-8"?>
<foo>
    <bar>
        <date attrib1='aaaaaaa' attrib2='0'>25-02-08</date>
                                         ^
        <name attrib3='null'>AAAAAAAAAAAAAAA</name>
    </bar>
    <bar>
        <date attrib1='cccccc' attrib2='0'>26-02-08</date>
                                        ^
        <name attrib4='null'>BBBBBBBBBBBBBBB</name>
    </bar>
</foo>

Can somebody please suggest the correct stylesheet?

I am blindly typing mainly 'copy' or 'copy-of' in my templates and the
output generation mechanics make little sense to me. The docs, comparing
to other programing documentation seems hard to understand. Could
somebody suggest good docs, please?

Regards,
Karol

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Jeferson L. Sese
jeferson dot sese at asiatype dot com
Asiatype Inc.
Suite 114 Columbia Tower
Ortigas Ave., Greenhills
Mandaluyong City 1550 Philippines
Tel: +632-744-6262
Mobile: +63927-671-7901




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