You say you want to combine all the documents into one big document. You can
certainly do that, for example
<xsl:variable name="bigDoc">
<xsl:copy-of select=="collection(...)"/>
</xsl:variable>
But you also say that this gives you memory problems. So I think you need to
explain why you feel you need to do this. You say "I need to be able to
traverse the entire collection" but that doesn't appear to justify doing it
this way.
What transformation are you actually trying to perform?
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Craig Branham [mailto:ccbranham(_at_)hotmail(_dot_)com]
Sent: 28 April 2008 17:41
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Working with Collections
Dear List:,
I have a set of large input files (all with the same
structure) to process with collection() and an external
collection file that shows which input files to process, and
in what order, to a single output file.
Is there a way to join all these documents below the top
level element and process their contents as though they were
a single input file?
A <xsl:for-each/> approach processes each document in the
collection in turn, which I don't want (I need to be able to
traverse the entire
collection):
<xsl:template match="/">
<mytop>
<xsl:for-each select="collection('collection.xml')">
<xsl:apply-templates select="yourtop/yourcontent"/>
</xsl:for-each>
</mytop>
</xsl:template>
I could also abandon using collections and use:
<xsl:apply-templates
select="...|document('x')/...|document('y')/..."/>
but I would rather have a separate collection file for
extensibility and flexibility if possible.
I've tried creating a temporary tree, but have run into
memory problems doing this that I'd rather not deal with.
Does anyone have any advice?
Many Thanks,
Craig B.
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