Of course it should be != rather than =! - but I wonder if that was really
your problem?
You can also write
<xsl:value-of select="crosslist[. != 'none']"/>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Michelle Tarby [mailto:tarbymm(_at_)lemoyne(_dot_)edu]
Sent: 08 May 2008 19:03
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Help with an xsl:if
I can't figure out what I'm doing wrong with this statement.
If I take out the xsl:if, everything displays properly, but
I'd like to only display crosslist if there's something other
than none as a value:
<xsl:for-each select="fll/class">
<xsl:value-of select="number"/>.
<xsl:value-of select="title"/>
(<xsl:value-of select="credits"/>)
<xsl:if test="crosslist=!'none'">
<xsl:value-of select="crosslist" />
</xsl:if>
<xsl:value-of select="prereq"/><br />
<xsl:value-of select="description"/><br /><br /> </xsl:for-each>
Any suggestions would be appreciated.
--
Michelle Tarby
Director of Web Services
Information Technology
Le Moyne College
http://www.lemoyne.edu
tarbymm(_at_)lemoyne(_dot_)edu
*****************************
"That's the beauty of tomorrow. There is no such thing as a
setback. The lessons I learn today I will apply tomorrow, and
I will be better."
- Tiger Woods
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