Excellent! Thank you very much for your help.
--- Martin Honnen <Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
sudheshna iyer wrote:
I am using xsl:stylesheet version="1.0".
Here is an XSLT 1.0 stylesheet that produces the
result you described.
You only need to complete the "translation table"
for the months:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:dt="http://example.com/2008/data";
version="1.0">
<xsl:output method="text"/>
<data xmlns="http://example.com/2008/data";>
<month s="Jan" n="01"/>
<month s="Feb" n="02"/>
<month s="Mar" n="03"/>
<month s="Apr" n="04"/>
<!-- add other months here -->
</data>
<xsl:template match="/">
<xsl:apply-templates select="rss/channel/item">
<xsl:sort data-type="number"
order="descending"
select="concat(substring(SortDate, 13, 4),
document('')/xsl:stylesheet/dt:data/dt:month[(_at_)s =
substring(current()/SortDate, 9, 3)]/@n,
substring(SortDate, 6, 2))"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="item">
<xsl:value-of
select="concat(substring(SortDate, 13, 4), '-',
document('')/xsl:stylesheet/dt:data/dt:month[(_at_)s =
substring(current()/SortDate, 9, 3)]/@n, '-',
substring(SortDate, 6, 2),
'
', title, '
')"/>
</xsl:template>
</xsl:stylesheet>
--
Martin Honnen
http://JavaScript.FAQTs.com/
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