As an extension to the below one, I need to combine
feeds from two diff sources and sort on date though
the feeds have diff elements:
File1.xml:
<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0"
xmlns:aaa="http://www.aaa.org/bbb/aaa_Spec/">
<channel>
<title>Title1</title>
<link>link1</link>
<description>Description 1</description>
<language>en-us</language>
<item>
<title>item 1</title>
<description>item desc 1</description>
<SortDate>Wed, 18 Feb 2008 11:18:41
-0000</SortDate>
<link>item link1</link>
<guid>item guid1 </guid>
<aaa:modelDate>Sat, 15 Mar 2008 12:18:41
-0000</aaa:modelDate>
</item>
<item>
<title>item 2</title>
<description>item desc 2</description>
<SortDate>Wed, 19 Feb 2008 11:18:41
-0000</SortDate>
<link>item link1</link>
<guid>item guid1 </guid>
<aaa:modelDate>Sat, 16 Mar 2008 12:18:41
-0000</aaa:modelDate>
</item>
</channel>
</rss>
File2.xml
<?xml version="1.0" encoding="UTF-8"?>
<Annoucements>
<announcement>
<anc_date>2008-03-11</anc_date>
<anc_title>Annoucement Title1</anc_title>
</announcement>
<announcement>
<anc_date>2008-07-14</anc_date>
<anc_title>Annoucement Title2</anc_title>
</announcement>
</Annoucements>
I should be able to combine File12.xml and File2.xml,
sort them by date in desc order and display the
output in the following format.
Output format:
Annoucement Title2
14 Jul 2008
Annoucement Title1
11 Mar 2008
item 1
19 Feb 2008
item 2
18 Feb 2008
How can achieve this?
--- sudheshna iyer <sudheshnaiyer(_at_)yahoo(_dot_)com> wrote:
Excellent! Thank you very much for your help.
--- Martin Honnen <Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
sudheshna iyer wrote:
I am using xsl:stylesheet version="1.0".
Here is an XSLT 1.0 stylesheet that produces the
result you described.
You only need to complete the "translation table"
for the months:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dt="http://example.com/2008/data"
version="1.0">
<xsl:output method="text"/>
<data xmlns="http://example.com/2008/data">
<month s="Jan" n="01"/>
<month s="Feb" n="02"/>
<month s="Mar" n="03"/>
<month s="Apr" n="04"/>
<!-- add other months here -->
</data>
<xsl:template match="/">
<xsl:apply-templates
select="rss/channel/item">
<xsl:sort data-type="number"
order="descending"
select="concat(substring(SortDate, 13,
4),
document('')/xsl:stylesheet/dt:data/dt:month[(_at_)s =
substring(current()/SortDate, 9, 3)]/@n,
substring(SortDate, 6, 2))"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="item">
<xsl:value-of
select="concat(substring(SortDate, 13, 4), '-',
document('')/xsl:stylesheet/dt:data/dt:month[(_at_)s =
substring(current()/SortDate, 9, 3)]/@n, '-',
substring(SortDate, 6, 2),
'
', title, '
')"/>
</xsl:template>
</xsl:stylesheet>
--
Martin Honnen
http://JavaScript.FAQTs.com/
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