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Re: [xsl] Directory listing, as xml file

2008-06-01 02:14:46
That depends too much on your platform to say. Is this XSL-T meant to
run in a filesystem, or is it meant to be running on a server and then
doing a HTTP GET on an address that represents a folder of files?

If in the filesystem then what filesystem, and anyway I don't think
there is a way to do it by the file uri scheme definition, however
maybe specific implementations of the file uri scheme would allow you
to give a folder path like file:///c:/ on Windows for example and get
a list of files back. I don't think so though.

Maybe a particular implementation will do this with file uris for you
though? Thus your xsl-t would be processor specific.


Cheers,
Bryan Rasmussen

On Sun, Jun 1, 2008 at 11:05 AM, Dave Pawson 
<davep(_at_)dpawson(_dot_)co(_dot_)uk> wrote:
I want to generate a list of elements
which constitutes all the xml files in
a directory, say ./sub

<reference
          xmlns:xi='http://www.w3.org/2001/XInclude'>
<title> Element Reference</title>
<xi:include href='intro-elements.xml'/>

<xi:include href='sub/a.xml'/>
<xi:include href='sub/b.xml'/>
<xi:include href='sub/c.xml'/>

....


</reference>

Any suggestions how this might be done (mostly) with xslt?
I'm also trying to minimize the OS dependence.


TIA

regards

--
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk

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