Thank you for the reply.
I have the following xsl file:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xalan="http://xml.apache.org/xalan";>
<xsl:key name="keyname" match="subroot" use="ccc"/>
<xsl:template match="root">
<xsl:variable name="var">
<xsl:element name="root">
<xsl:element name="subroot">
<xsl:apply-templates
select="file_entry"/>
</xsl:element>
</xsl:element>
</xsl:variable>
<!--Traverse the variable-->
<xsl:for-each select="xalan:nodeset($var)/root">
<xsl:variable name="test" select="key('keyname',
'11')"/>
<xsl:text>inside root.....: </xsl:text>
<xsl:for-each select="$test">
==============> Why is this test var empty???
<xsl:text>inside test.....: </xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
<xsl:template match="subroot">
<xsl:element name="subroot">
<xsl:element name="ccc">
<xsl:apply-templates select="ccc" mode="copy"/>
</xsl:element>
<xsl:element name="ddd">
<xsl:apply-templates select="ddd" mode="copy"/>
</xsl:element>
<xsl:element name="eee">
<xsl:apply-templates select="eee" mode="copy"/>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
For the following xml:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
<subroot id="11111">
<ccc>22</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
</root>
I put the key in xsl:sheet and called where I need. But I am not sure why test
variable is empty?
Shouldn't it contain two subroots that match from the above xml which has 3
subroots?
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
--- On Fri, 7/25/08, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Subject: RE: [xsl] create xml from incoming xml and load it into a variable
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Friday, July 25, 2008, 4:57 PM
Well, you can't use xsl:key anywhere other other than as
a child of
xsl:stylesheet.
How to correct your code depends rather on what you thought
your code was
intended to mean. I suspect you want the xsl:key as
written, but moved to
the right place, and a call on the key() function where you
currently have
the xsl:key element.
Remember that an xsl:key declaration is not tied to a
specific document or
tree. It's the call on key() that determines which tree
will be searched.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: sudheshna iyer [mailto:sudheshnaiyer(_at_)yahoo(_dot_)com]
Sent: 25 July 2008 21:37
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] create xml from incoming xml and
load it
into a variable
Thank you.
I did this using:
<xsl:template match="root">
<xsl:variable name="var">
<xsl:element name="subroot"
use-attribute-sets="id">
<xsl:apply-templates select="bbb"/>
</xsl:element>
</xsl:variable>
<!--Traverse the variable-->
<xsl:for-each
select="xalan:nodeset($var)/root/subroot">
<xsl:key name="ccc"
match="subroot" use="11"/> ===>
ERROR!!!!
</xsl:for-each>
</xsl:template>
Sample xml:
<?xml version="1.0"
encoding="UTF-8"?>
<root>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
<subroot id="11111">
<ccc>22</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaaaaa</eee>
</subroot>
</root>
Inside the loop, I need to use <xsl:key
name="ccc"
match="subroot" use="ccc"/>.
But while transforming, I am receiving the following
error:
xsl:key is not allowed in this position in the
stylesheet!
How do I use "key" tag inside a variable
which contains xml?
I appreciate your help.
--- On Fri, 7/25/08, Andrew Welch
<andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com> wrote:
From: Andrew Welch
<andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com>
Subject: Re: [xsl] create xml from incoming xml
and load it into a
variable
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Friday, July 25, 2008, 6:02 AM
2008/7/25 sudheshna iyer
<sudheshnaiyer(_at_)yahoo(_dot_)com>:
How do I create xml from incoming xml and
load it into
a variable from xsl? Afterr loading I
have to loop through the variable for doing
more xsl
transformations?
My xsl has incoming xml. I have to create
another xml
of different format, put it in a variable
and loop through that variable to apply more
xsl
transformations.
Do the first pass in a variable:
<xsl:variable name="first-pass">
<xsl:apply-templates
mode="first-pass"/> </xsl:variable>
The do the second pass by calling apply-templates
on the first pass:
<xsl:apply-templates
select="$first-pass"/>
...or something similar - you may want to mode
the second
pass if it's
less work. Remember to have two root match
templates, one
moded, to
ensure do don't get infinite recursion.
If the first pass could be a one-off batch
process, then
you're better
off separating out the transforms than repeatedly
doing the
first pass
each time.
--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/
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