Thank you. This is exactly what I want.
--- On Tue, 7/29/08, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Subject: RE: [xsl] create xml from incoming xml and load it into a variable
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Tuesday, July 29, 2008, 6:52 AM
Unfortunately the output of xsl:message is
implementation-defined. Your XSLT
processor appears to be flattening it to a string, which I
don't think is a
particularly good idea, but it's allowed by the spec.
(Some processors
discard xsl:message output completely, which is also
permitted.)
You can also view the variable by copying it temporarily to
the result tree:
<debug variable="var">
<xsl:copy-of select="$var"/>
</debug>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: sudheshna iyer [mailto:sudheshnaiyer(_at_)yahoo(_dot_)com]
Sent: 29 July 2008 11:30
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] create xml from incoming xml and
load it
into a variable
Thank you for the reply.
If I use
<xsl:message>
var: <xsl:copy-of select="$var"/>
</xsl:message>
It only prints the following for the below mentioned
xml:
112005-08-26aaaaaaaaaa11111222005-08-26bbbbb112005-08-26ccccc1
12005-08-26dddddddddd11111
For the xml:
<?xml version="1.0"
encoding="UTF-8"?>
<root>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaa</eee>
<eee>aaaaa11111</eee>
</subroot>
<subroot id="11111">
<ccc>22</ccc>
<ddd>2005-08-26</ddd>
<eee>bbbbb</eee>
</subroot>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>ccccc</eee>
</subroot>
<subroot id="11111">
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>ddddd</eee>
<eee>ddddd11111</eee>
</subroot>
</root>
I want to see the complete xml, just like the input
xml along
with element names.
For eg:
<root>
<ccc>11</ccc>
<ddd>2005-08-26</ddd>
<eee>aaaaa</eee>
<eee>aaaaa11111</eee>
...
with the hiearchy preserved. I am debugging larger xsl
file
and I don't know whether result-tree in the memory
is
constructed right or not.
Thank you.
--- On Tue, 7/29/08, Florent Georges
<lists(_at_)fgeorges(_dot_)org> wrote:
From: Florent Georges <lists(_at_)fgeorges(_dot_)org>
Subject: Re: [xsl] create xml from incoming xml
and load it into a
variable
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Tuesday, July 29, 2008, 5:57 AM
sudheshna iyer wrote:
Hi
In the below xsl, how do I see the entire
xml that is
in
variable "var"?
What do you mean exactly? If you want to
"see"
it in the result
tree, use xsl:sequence or xsl:copy-of:
<bla-bla>
<xsl:copy-of
select="$var"/>
</bla-bla>
If you want to "see" it on the
console (or whatever your
environment
directs messages to), for debugging purpose, you
can use
xsl:messages:
<xsl:message select="$var"/>
<!-- or... -->
<xsl:message>
VAR: <xsl:copy-of
select="$var"/>
</xsl:message>
Regards,
--drkm
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