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Re: [xsl] flattening and re-ordering nested notes

2008-08-18 11:33:41
Thanks again.

On Aug 18, 2008, at 12:06 PM, Andrew Welch wrote:

<xsl:template match="@*|node()" mode="#all">
        <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
</xsl:template>

<xsl:template match="note"/>

<xsl:template match="document">
        <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
        <xsl:apply-templates select="//note" mode="notes"/>
</xsl:template>

</xsl:stylesheet>


Would this be the equivalent in 1.0 syntax, or am I missing something basic? (I am getting some strange results with missing IDs, and I wonder if I'm not being specific enough on the mode="notes" part.)

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/ Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes" />
<xsl:template match="@*|node()">
        <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
</xsl:template>
<xsl:template match="@*|node()" mode="notes">
        <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
</xsl:template>

<xsl:template match="note"/>

<xsl:template match="document">
        <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
<xsl:apply-templates select="//note[not(@type='margin' or @type='sourcenote')]" mode="notes"/>
        </xsl:copy>
</xsl:template>

</xsl:stylesheet>


Thanks,

Walter

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