Thanks. I was thinking that sort gets applied to output if it's put
inside xsl:apply-templates, but it looks like it just works on input.
Thanks for the explanation.
Is there a way I could do this in one xslt itself?
On Tue, Sep 9, 2008 at 11:57 AM, Wendell Piez
<wapiez(_at_)mulberrytech(_dot_)com> wrote:
Mohit,
In order to understand where to put the xsl:sort instruction, you need to
understand what it does. It really isn't "sorting" anything. XSLT is a
declarative language, so any XSLT stylesheet is really a specification for
how an XSLT processor is supposed to build its result out of its input.
Along these lines, xsl:sort overrides the processor's ordinary behavior, in
which the order of the results corresponds to the order of elements in the
input from which the results are built, and instead corresponds to a sorted
order in the input.
So you're not really "apply[ing] sort" on any output, merged or not. If you
really want to sort your output, the easiest way to do that is to run a
second transformation in which your input is the output of the first
transformation.
And what you'd want is probably something like (what you said you've tried)
<xsl:for-each select="//ret|$file2//ret">
<xsl:sort select="filing" order="ascending" data-type="text"/>
<xsl:sort select="State" order="ascending" data-type="number"/>
Assuming your input 'ret' elements all have both 'filing' and 'State' child
elements.
Now why isn't this working? You say your sort on 'filing' is working, only
the 'ret' elements from the two input documents are not sorted together.
This might well be a bug in your processor, which might have evaded
detection since this is actually a fairly rare thing to be doing. Careful
testing can determine this, but in the meantime you might try something
like:
<xsl:variable name="merged-set" select="//ret|$file2//ret"/>
<xsl:for-each select="$merged-set">
<xsl:sort ...
Conceivably, this could fool the processor into treating the two sets of
nodes as one, as you want them to be treated.
Even if this works, you should tell us what processor you are using so that
others may try to duplicate the bug, if that's what it is. (Several
developers of processors monitor this list to see what bugs might be
reported.)
As to why your sort on 'State' elements is not working, you need to show us
your input data (again?) if we are to see what could be going wrong there.
Without seeing the input (which you should post in reduced form with your
question, so the email is self-contained and does not require us to look
back in the archive ), it's really impossible to know anything for certain.
Cheers,
Wendell
At 02:10 PM 9/9/2008, you wrote:
I have 2 xml that I am merging, something like this:
<xsl:for-each select="//ret|$file2//ret">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:apply-templates>
<xsl:sort select="filing" order="ascending"
data-type="text"/>
<xsl:sort select="State" order="ascending"
data-type="number"/>
</xsl:apply-templates>
</xsl:element>
</xsl:for-each>
Couple of questions:
1. Above xsl:for-each merges 2 xml documents. Now I want to apply sort
on the merged output. I tried putting sort inside apply-templates as
well as moving inside for-each. It doesn't seem to work. I am trying
to sort on 2 elements. Is there a way I can sort on merged output.
2. Also, when I put sort in for-each it sort only one document at a
time, but second sort on "State" doesn't work.
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