There are no built-in functions for parsing dates in non-standard formats
(as distinct from formatting them), but you can do it easily enough using
regular expressions and xsl:analyze-string.
The precise solution depends on a precise definition of your input format,
which you haven't given us.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Pankaj Chaturvedi [mailto:pankaj(_dot_)chaturvedi(_at_)idsil(_dot_)com]
Sent: 16 September 2008 09:49
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Date YYYYMMDD format XSLT 2.0
Hi,
I have an element which has the date in the below format in
an attribute:
Input
================
<chapter version="Feb. 2000"/>
The date could be optional can be taken as 01 by default. So
the desired output required in "YYYYMMDD format".
Output Required
================
<chapter version="20000201"/>
I've been going thru the Michael Kay's book and found it has
an example which does the trick vice versa. I mean YYYYMMDD
to 01 Feb 2000 for instance.
I am using the XSLT 2.0 and thinking of using translate()
functions (for
months) to get this done. Is there any better way to achieve
this? Any suggestions will be highly appreciated.
Best,
Pankaj Chaturvedi
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