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RE: [xsl] Date YYYYMMDD format XSLT 2.0 (with string Update)

2008-09-16 08:43:14
 
<chapter version="Feb. 2000"/>
<chapter version="Oct. 2006 Update">


Apart from this I need to ignore attributes values with "Update" (<chapter
version="Dec. 2003 Update">) which I will be able to handle with string
check (contains() function)



========
Once again, is the below code is correct for "xsl:analyze-string" for cases
where @version contains string ' Update'. 

<xsl:analyze-string select="substring-before(string(./@version), ' Update')"
regex="{ $re }">

 seems to error in select="" though XMLSpy does not gives any error. I am
trying to conditional test of @version with and without 'Update' string.

Thanks

 

-----Original Message-----
From: Pankaj Chaturvedi [mailto:pankaj(_dot_)chaturvedi(_at_)idsil(_dot_)com]
Sent: 16 September 2008 09:49
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Date YYYYMMDD format XSLT 2.0


Hi,

I have an element which has the date in the below format in an
attribute:

Input
================
<chapter version="Feb. 2000"/>

The date could be optional can be taken as 01 by default. So the 
desired output required in "YYYYMMDD format".

Output Required
================
<chapter version="20000201"/>


I've been going thru the Michael Kay's book and found it has an 
example which does the trick vice versa. I mean YYYYMMDD to 01 Feb 
2000 for instance.

I am using the  XSLT 2.0 and thinking of using translate() functions 
(for
months) to get this done. Is there any better way to achieve this? Any 
suggestions will be highly appreciated.

Best,

Pankaj Chaturvedi

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