Hi Mailinglist,
I have an xml file like this:
<wrapper class=”menu”>
<title>menu1</title>
<section>
<title>Indoor climate</title>
<table> some table here</table>
<section>
<title> under menus</title>
<paragraph>some text here</paragraph>
</section>
<wrapper class=”menu”>
<title>menu1.1</title>
<section>
<title>Temperatur</title>
<paragraph>some text here</paragraph>
</section>
<wrapper class=”menu”>
<title>menu1.1.1</title>
<section>
<title>Heat</title>
<paragraph>some text here</paragraph>
</section>
<wrapper class=”menu”>
<title>menu1.1.1.1</title>
<section>
<title>Heat2</title>
<paragraph>some text here</paragraph>
</section>
</wrapper>
</wrapper>
</wrapper>
</section>
</wrapper>
I want to select all the children of the wrapper, except the children wrappers.
I mean I want to select i.e from the first wrapper just title,
section,section/title, section/table and section/section,but not the child
wrapper, and from the child wrapper, I want to select all its children except
the child wrapper, and so on.
I tried to write :
<xsl: for-each select=”wrapper[(_at_)class=’menu’]>
<xsl:apply-templates select=*[not(descendant::wrapper[wrapper=’menue’])]/>
</xsl:for-each>
But this dos not work. Any ideas please
Thank you in advance
Matilda
__________________________________________________________
Går det långsamt? Skaffa dig en snabbare bredbandsuppkoppling.
Sök och jämför priser hos Kelkoo.
http://www.kelkoo.se/c-100015813-bredband.html?partnerId=96914325
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--