RE: [xsl] Excluding a complete branch while identity copying

Empty template matches will omit those from the output:

<!--Identity template-->
<xsl:template match="@*|*">
    <xsl:copy>
      <xsl:apply-templates select="@*"/>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>
  
<--empty templates override the identity transform for specified
matches-->
  <xsl:template match="Evens | Squares"/> 

HTH,
Ryan

-----Original Message-----
From: Fraser Goffin [mailto:goffinf(_at_)googlemail(_dot_)com] 
Sent: Friday, October 10, 2008 10:44 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Excluding a complete branch while identity copying

I want to be able to copy a complete XML instance as/is except for [say]
some specific parts of the input tree. I thought immediately of using an
identity transform and specifying copy, but how to remove those pesky
sub-trees :-

Say this was my input :-

<Numbers>
        <Odds>
                <One>1</One>
                <Three>3</Three>
                <Five>5</Five>
        </Odds>
        <Evens>
                <Two>2</Two>
                <Four>4</Four>
                <Six>6</Six>
        </Evens>
        <Doubles>
                <Two>4</Two>
                <Four>8</Four>
                <Eight>16</Eight>
        </Doubles>
        <Squares>
                <Two>4</Two>
                <Four>16</Four>
                <Eight>64</Eight>
        </Squares>
</Numbers>

and I want to copy everything to output except <Evens> and <Squares>.

Lets also assume that the order of the input is undefined, so Evens and
Squares may/may not be in the positions I have shown above, although I
can assume that they are both children of <Numbers>.
Further, I don't know what all the children of Evens and Squares are
called I just know I don't want them.

Whats the easiest way of accomplishing this ?

many thanks

Fraser.

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