In XSLT 2.0 it's simply
distinct-values(//*/name())
distinct-values(//@*/name())
If you really need to do it with XSLT 1.0, eliminating duplicates is
essentially the same problem as grouping, and you can use the Muenchian
grouping approach.
The preceding-sibling grouping technique isn't going to work (a) because
your nodes are not siblings of each other, and (b) because it only works
where the grouping key is the string-value of the node, not where it is some
other function of the node (here, it's name). Muenchian grouping works for
any string-valued function of a node.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ganesh Babu N [mailto:nbabuganesh(_at_)gmail(_dot_)com]
Sent: 28 October 2008 09:38
To: XSL
Subject: [xsl] Extracting Unique element names and attributes
from a XML file
Hai All,
I need to list out all elements and attribute (unique) in a
text file for mapping with other XML file.
I am able to get all the elements and attributes but I am
unable to achieve the uniqueness. Can any body help on this.
I have tested with <xsl:sort> and not(preceding-sibling::* =
current()). Still I am unable to get the uniqueness.
My XSL is follows:
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:for-each select="//*">
<xsl:value-of select="local-name(.)"/>
<xsl:text> </xsl:text>
<xsl:choose>
<xsl:when test="@*">
<xsl:for-each
select="@*">@<xsl:value-of select="local-name(.)"/><xsl:text>
</xsl:text>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:text>
</xsl:text>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Regards,
Ganesh
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