Here is a different algorithm, than Mike
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:output method="text" />
<xsl:template match="Orders">
<xsl:for-each-group select="*" group-starting-with="StartOrderGroup">
<xsl:text>
Order
</xsl:text>
<xsl:text>-----
</xsl:text>
<xsl:variable name="curr-group" select="current-group()" />
<xsl:variable name="indx" select="index-of(for $x in $curr-group
return $x/local-name(), 'EndOrderGroup')" />
<xsl:for-each select="$curr-group[position() > 1 and
position() < $indx]">
<xsl:value-of select="local-name()" /> - <xsl:value-of
select="Id" /><xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
On Mon, Dec 22, 2008 at 4:07 PM, Fredde Hedberg
<syte_orion(_at_)yahoo(_dot_)com> wrote:
The problem is solvable with XSLT, provided your input XML
is well
formed. But your input is not a valid XML document.
for e.g., <Id=1/> is not a valid XML fragment, and
XML parser
complains about it.
My mistake, I apologize. When I simplified my XML I made it more bad formed
than it really is...
<Orders>
<StartOrderGroup>
<Id>1</Id>
</StartOrderGroup>
<Car>
<Id>2</Id>
</Car>
<Car>
<Id>3</Id>
</Car>
<Bus>
<Id>4</Id>
</Bus>
<EndOrderGroup>
<Id>5</Id>
</EndOrderGroup>
<Car>
<Id>6</Id>
</Car>
<Truck>
<Id>7</Id>
</Truck>
<StartOrderGroup>
<Id>8</Id>
</StartOrderGroup>
<Truck>
<Id>9</Id>
</Truck>
<EndOrderGroup>
<Id>10</Id>
</EndOrderGroup>
</Orders>
That's at least valid XML :)
You've given me hope by saying it is solvable. Will this new XML-fragment
allow you to show me how? That would basically save christmas for me...
Regards
Fredde
--
Regards,
Mukul Gandhi
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--