I don't think you can do this join in a single XPath 1.0 expression. It
either needs XPath 2.0, or some kind of xsl:for-each logic if you really
must do it in XSLT 1.0.
If you can find a solution in XPath 2.0 or XSLT 1.0, I will take it.
I don't know how you can define a variable using xsl:for-each: you
cannot redefine variables and there is no breaking from a loop.
--
Andrew Ferk
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